In the previous chapters, we practiced Simple Interest Questions and Compound Interest Questions separately. Now it’s time to bring both concepts together and understand how they differ in real-world situations.
This chapter focuses on Difference Between Simple Interest and Compound Interest Questions, one of the most important topics for SSC, RRB, Banking, Defence, Police, and other competitive examinations. The questions are arranged from easy to exam level, helping you gradually build confidence and improve your problem-solving skills.
Before attempting these questions, we recommend revising the important formulas from our Simple Interest & Compound Interest Formula page. A strong understanding of both concepts will help you solve these questions quickly and accurately.
To strengthen your Quantitative Aptitude preparation, you can also explore our:
- Maths Notes for detailed concept explanations
- Maths Formula Section for quick revision
- Practice Questions for every Quantitative Aptitude chapter
- Previous Year Questions (PYQs) from SSC, RRB, Banking, Defence, Police, and other competitive examinations
- Quantitative Aptitude Syllabus to understand the topics covered in different competitive exams
- Math Calculators to verify your answers and improve your understanding
Now, challenge yourself by solving each question without looking at the solution first. Once you’ve attempted the question, compare your approach with the detailed solution to identify mistakes and improve your speed and accuracy.
Quick Note: SI & CI Difference Formulas
| Formula | Expression |
| General Formula | Difference (CI − SI) = Compound Interest − Simple Interest |
| For 2 Years | Difference (CI − SI) = (P × R²) ÷ 100² |
| For 3 Years | Difference (CI − SI) = P × R² × (300 + R) ÷ 100³ |
Question 1: During a financial awareness camp at Parade, Kanpur, two friends each deposited ₹25,000 for 2 years at 10% per annum.
- Aman chose Simple Interest.
- Bharat chose Compound Interest, compounded annually.
Calculate:
- Simple Interest earned by Aman.
- Compound Interest earned by Bharat.
- By how much did Bharat earn more than Aman?
Solution
Given
Principal Amount (P) = ₹25,000
Rate of Interest (R) = 10% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (25,000 × 10 × 2) ÷ 100
= ₹5,000
Step 2: Calculate the Compound Interest
Amount
= 25,000 × (1 + 10/100)²
= 25,000 × (1.10)²
= 25,000 × 1.21
= ₹30,250
Compound Interest
= ₹30,250 − ₹25,000
= ₹5,250
Step 3: Compare the Two
Difference
= Compound Interest − Simple Interest
= ₹5,250 − ₹5,000
= ₹250
Answer
- Simple Interest earned by Aman = ₹5,000
- Compound Interest earned by Bharat = ₹5,250
- Bharat earned ₹250 more than Aman.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹25,000 | ₹25,000 |
| Rate | 10% | 10% |
| Time | 2 years | 2 years |
| Interest Earned | ₹5,000 | ₹5,250 |
| Difference | — | ₹250 More |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
For 2-year questions, you can quickly find the difference between Compound Interest and Simple Interest using the shortcut:
Difference (CI − SI) = (P × R²) ÷ 100²
Applying the formula:
= (25,000 × 10²) ÷ 100²
= (25,000 × 100) ÷ 10,000
= ₹250
Note: This shortcut is applicable only for 2-year questions.
Question 2: A family planning a vacation to Puri Beach invested ₹40,000 for 3 years at 8% per annum.
Calculate:
- Simple Interest
- Compound Interest
- Difference between the two interest amounts.
Solution
Given
Principal Amount (P) = ₹40,000
Rate of Interest (R) = 8% per annum
Time (T) = 3 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)³
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (40,000 × 8 × 3) ÷ 100
= ₹9,600
Step 2: Calculate the Compound Interest
Amount
= 40,000 × (1 + 8/100)³
= 40,000 × (1.08)³
= 40,000 × 1.259712
= ₹50,388.48
Compound Interest
= ₹50,388.48 − ₹40,000
= ₹10,388.48
Step 3: Calculate the Difference
Difference
= Compound Interest − Simple Interest
= ₹10,388.48 − ₹9,600
= ₹788.48
Answer
- Simple Interest = ₹9,600
- Compound Interest = ₹10,388.48
- Difference = ₹788.48
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹40,000 | ₹40,000 |
| Rate | 8% p.a. | 8% p.a. |
| Time | 3 years | 3 years |
| Interest Earned | ₹9,600 | ₹10,388.48 |
| Difference | — | ₹788.48 More |
Question 3: A Pharmacist in Indian Railways invested ₹60,000 for 2 years at 12% per annum.
Calculate:
- Amount under Simple Interest
- Amount under Compound Interest
- Difference between the maturity amounts.
Solution
Given
Principal Amount (P) = ₹60,000
Rate of Interest (R) = 12% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Amount under Simple Interest
Simple Interest
= (60,000 × 12 × 2) ÷ 100
= ₹14,400
Amount
= Principal + Simple Interest
= ₹60,000 + ₹14,400
= ₹74,400
Step 2: Calculate the Amount under Compound Interest
Amount
= 60,000 × (1 + 12/100)²
= 60,000 × (1.12)²
= 60,000 × 1.2544
= ₹75,264
Step 3: Calculate the Difference
Difference
= Compound Interest Amount − Simple Interest Amount
= ₹75,264 − ₹74,400
= ₹864
Answer
- Amount under Simple Interest = ₹74,400
- Amount under Compound Interest = ₹75,264
- Difference between the maturity amounts = ₹864
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹60,000 | ₹60,000 |
| Rate | 12% p.a. | 12% p.a. |
| Time | 2 years | 2 years |
| Maturity Amount | ₹74,400 | ₹75,264 |
| Difference | — | ₹864 More |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
Since this is a 2-year question, you can directly calculate the difference between the maturity amounts using the shortcut:
Difference (CI − SI) = (P × R²) ÷ 100²
= (60,000 × 12²) ÷ 100²
= (60,000 × 144) ÷ 10,000
= ₹864
Question 4: A spare-parts dealer in the Auto Market, Hisar borrowed ₹80,000 for 3 years at 10% per annum.
How much extra interest would he pay if the loan used Compound Interest instead of Simple Interest?
Solution
Given
Principal Amount (P) = ₹80,000
Rate of Interest (R) = 10% per annum
Time (T) = 3 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)³
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (80,000 × 10 × 3) ÷ 100
= ₹24,000
Step 2: Calculate the Compound Interest
Amount
= 80,000 × (1 + 10/100)³
= 80,000 × (1.10)³
= 80,000 × 1.331
= ₹1,06,480
Compound Interest
= ₹1,06,480 − ₹80,000
= ₹26,480
Step 3: Calculate the Extra Interest
Extra Interest
= Compound Interest − Simple Interest
= ₹26,480 − ₹24,000
= ₹2,480
Answer
The spare-parts dealer would pay ₹2,480 more if the loan used Compound Interest instead of Simple Interest.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹80,000 | ₹80,000 |
| Rate | 10% p.a. | 10% p.a. |
| Time | 3 years | 3 years |
| Interest Payable | ₹24,000 | ₹26,480 |
| Extra Interest | — | ₹2,480 More |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
Whether the money is invested or borrowed, the calculation method remains the same.
- Investment: Higher Compound Interest means more earnings.
- Loan: Higher Compound Interest means more interest payable.
Always read the question carefully to understand whether the difference represents an additional gain or an additional cost.
Question 5:A trader earned a 20% profit on selling motorcycle accessories in Auto Market, Hisar and invested the entire profit of ₹48,000 at 10% per annum for 2 years.
Find the difference between Compound Interest and Simple Interest earned on this investment.
(Students who are unsure how the ₹48,000 profit was determined can revise the Profit, Loss & Discount chapter.)
Solution
Given
Principal Amount (P) = ₹48,000
Rate of Interest (R) = 10% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (48,000 × 10 × 2) ÷ 100
= ₹9,600
Step 2: Calculate the Compound Interest
Amount
= 48,000 × (1 + 10/100)²
= 48,000 × (1.10)²
= 48,000 × 1.21
= ₹58,080
Compound Interest
= ₹58,080 − ₹48,000
= ₹10,080
Step 3: Calculate the Difference
Difference
= Compound Interest − Simple Interest
= ₹10,080 − ₹9,600
= ₹480
Answer
The difference between the Compound Interest and Simple Interest earned is ₹480.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹48,000 | ₹48,000 |
| Rate | 10% p.a. | 10% p.a. |
| Time | 2 years | 2 years |
| Interest Earned | ₹9,600 | ₹10,080 |
| Difference | — | ₹480 More |
Question 6: An engineer working at Jindal Steel, Jajpur invested ₹1,00,000 at 8% compound interest for 3 years.
Another engineer at Tata Steel invested the same amount for the same period at 8% simple interest.
Who earns more interest and by how much?
Solution
Given
Principal Amount (P) = ₹1,00,000
Rate of Interest (R) = 8% per annum
Time (T) = 3 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)³
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (1,00,000 × 8 × 3) ÷ 100
= ₹24,000
Step 2: Calculate the Compound Interest
Amount
= 1,00,000 × (1 + 8/100)³
= 1,00,000 × (1.08)³
= 1,00,000 × 1.259712
= ₹1,25,971.20
Compound Interest
= ₹1,25,971.20 − ₹1,00,000
= ₹25,971.20
Step 3: Compare the Interest Earned
Difference
= Compound Interest − Simple Interest
= ₹25,971.20 − ₹24,000
= ₹1,971.20
Answer
The engineer who invested at Compound Interest earns ₹1,971.20 more than the engineer who invested at Simple Interest.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹1,00,000 | ₹1,00,000 |
| Rate | 8% p.a. | 8% p.a. |
| Time | 3 years | 3 years |
| Interest Earned | ₹24,000 | ₹25,971.20 |
| Difference | — | ₹1,971.20 More |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
When the principal, rate, and time are the same, Compound Interest always earns more than Simple Interest for periods greater than one year because interest is earned on the accumulated interest every year.
Question 7: A resident of Unnao invested ₹50,000 at 12% per annum for 2 years.
Calculate the percentage by which the Compound Interest exceeds the Simple Interest.
(Related topic: Percentage.)
Solution
Given
Principal Amount (P) = ₹50,000
Rate of Interest (R) = 12% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (50,000 × 12 × 2) ÷ 100
= ₹12,000
Step 2: Calculate the Compound Interest
Amount
= 50,000 × (1 + 12/100)²
= 50,000 × (1.12)²
= 50,000 × 1.2544
= ₹62,720
Compound Interest
= ₹62,720 − ₹50,000
= ₹12,720
Step 3: Calculate the Difference
Difference
= Compound Interest − Simple Interest
= ₹12,720 − ₹12,000
= ₹720
Step 4: Calculate the Percentage by which Compound Interest Exceeds Simple Interest
Percentage Difference
= (Difference ÷ Simple Interest) × 100
= (720 ÷ 12,000) × 100
= 6%
Answer
The Compound Interest exceeds the Simple Interest by 6%.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹50,000 | ₹50,000 |
| Rate | 12% p.a. | 12% p.a. |
| Time | 2 years | 2 years |
| Interest Earned | ₹12,000 | ₹12,720 |
| Difference | — | ₹720 More (6%) |
Question 8: The elder brother invested under Simple Interest, while the younger brother invested under Compound Interest.
Both invested for 2 years at 10% per annum.
If the elder brother invested ₹45,000, calculate the difference between their interest earnings.
(Related topic: Ratio & Proportion.)
Solution
Given
Principal Amount (P) = ₹45,000
Rate of Interest (R) = 10% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (45,000 × 10 × 2) ÷ 100
= ₹9,000
Step 2: Calculate the Compound Interest
Amount
= 45,000 × (1 + 10/100)²
= 45,000 × (1.10)²
= 45,000 × 1.21
= ₹54,450
Compound Interest
= ₹54,450 − ₹45,000
= ₹9,450
Step 3: Calculate the Difference
Difference
= Compound Interest − Simple Interest
= ₹9,450 − ₹9,000
= ₹450
Answer
The younger brother earns ₹450 more in interest than the elder brother.
So,
| Particulars | Elder Brother (Simple Interest) | Younger Brother (Compound Interest) |
| Principal | ₹45,000 | ₹45,000 |
| Rate | 10% p.a. | 10% p.a. |
| Time | 2 years | 2 years |
| Interest Earned | ₹9,000 | ₹9,450 |
| Difference | — | ₹450 More |
Question 9:A person invested money at 10% per annum for 2 years.The Compound Interest exceeded the Simple Interest by ₹500.
Find the Principal Amount.
Solution
Given
Difference between Compound Interest and Simple Interest = ₹500
Rate of Interest (R) = 10% per annum
Time (T) = 2 years
Principal Amount (P) = ?
Formula Used
For 2 years,
Difference (CI − SI) = (P × R²) ÷ 100²
Step 1: Substitute the Given Values
500 = (P × 10²) ÷ 100²
Step 2: Simplify the Equation
500 = (P × 100) ÷ 10,000
500 = P ÷ 100
Step 3: Calculate the Principal
P = 500 × 100
= ₹50,000
Answer
The Principal Amount is ₹50,000.
So,
| Particulars | Value |
| Difference (CI − SI) | ₹500 |
| Rate | 10% p.a. |
| Time | 2 years |
| Principal | ₹50,000 |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
If the difference between Compound Interest and Simple Interest is given for 2 years, use the shortcut:
Principal = (Difference × 100²) ÷ R²
For this question,
Principal
= (500 × 100²) ÷ 10²
= (500 × 10,000) ÷ 100
= ₹50,000
Question 10: A Bank Manager introduced two investment plans.
- Plan A: Simple Interest at 10% per annum
- Plan B: Compound Interest at 10% per annum, compounded annually.
After 3 years, a customer found that Plan B earned ₹1,155 more interest than Plan A.
Find the Principal Amount.
Solution
Given
Difference between Compound Interest and Simple Interest = ₹1,155
Rate of Interest (R) = 10% per annum
Time (T) = 3 years
Principal Amount (P) = ?
Formula Used
For 3 years,
Difference (CI − SI) = P × R² × (300 + R) ÷ 100³
Step 1: Substitute the Given Values
1,155 = P × 10² × (300 + 10) ÷ 100³
Step 2: Simplify the Equation
1,155 = P × 100 × 310 ÷ 10,00,000
1,155 = 31P ÷ 1,000
Step 3: Calculate the Principal
31P = 1,155 × 1,000
31P = 11,55,000
P = 11,55,000 ÷ 31
= ₹37,258.06 (Approx.)
Answer
The Principal Amount is approximately ₹37,258.06.
So,
| Particulars | Value |
| Difference (CI − SI) | ₹1,155 |
| Rate | 10% p.a. |
| Time | 3 years |
| Principal | ₹37,258.06 (Approx.) |
Question 11: A resident of Parade, Kanpur purchased a laptop after receiving a 20% discount and saved ₹18,000.
He invested the entire savings for 2 years at 10% per annum.
Calculate the difference between Compound Interest and Simple Interest.
(Students can revise the Discount questions to understand how the savings were calculated.)
Solution
Given
Savings after discount (Principal Amount) = ₹18,000
Rate of Interest (R) = 10% per annum
Time (T) = 2 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)²
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (18,000 × 10 × 2) ÷ 100
= ₹3,600
Step 2: Calculate the Compound Interest
Amount
= 18,000 × (1 + 10/100)²
= 18,000 × (1.10)²
= 18,000 × 1.21
= ₹21,780
Compound Interest
= ₹21,780 − ₹18,000
= ₹3,780
Step 3: Calculate the Difference
Difference
= Compound Interest − Simple Interest
= ₹3,780 − ₹3,600
= ₹180
Answer
The Compound Interest exceeds the Simple Interest by ₹180.
So,
| Particulars | Simple Interest | Compound Interest |
| Principal | ₹18,000 | ₹18,000 |
| Rate | 10% p.a. | 10% p.a. |
| Time | 2 years | 2 years |
| Interest Earned | ₹3,600 | ₹3,780 |
| Difference | — | ₹180 More |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
Don’t get distracted by the 20% discount mentioned in the question. Since the saved amount (₹18,000) is already given, it directly becomes the principal for the interest calculation.
For 2-year questions, you can use the shortcut:
Difference (CI − SI) = (P × R²) ÷ 100²
= (18,000 × 10²) ÷ 100²
= (18,000 × 100) ÷ 10,000
= ₹180
Question 12: A Pharmacist in Indian Railways and a Station Master each invested ₹75,000 for 3 years.
- The Pharmacist chose Simple Interest at 9% per annum.
- The Station Master chose Compound Interest at 9% per annum, compounded annually.
Calculate:
- Simple Interest earned by the Pharmacist.
- Compound Interest earned by the Station Master.
- Difference in interest earned.
- Difference in maturity amounts.
- By what percentage did the Compound Interest exceed the Simple Interest?
Solution
Given
Principal Amount (P) = ₹75,000
Rate of Interest (R) = 9% per annum
Time (T) = 3 years
Formula Used
Simple Interest
SI = (P × R × T) ÷ 100
Compound Interest
Amount = Principal × (1 + R/100)³
Compound Interest = Amount − Principal
Step 1: Calculate the Simple Interest
Simple Interest
= (75,000 × 9 × 3) ÷ 100
= ₹20,250
Simple Interest Amount
= ₹75,000 + ₹20,250
= ₹95,250
Step 2: Calculate the Compound Interest
Amount
= 75,000 × (1 + 9/100)³
= 75,000 × (1.09)³
= 75,000 × 1.295029
= ₹97,127.18 (Approx.)
Compound Interest
= ₹97,127.18 − ₹75,000
= ₹22,127.18 (Approx.)
Step 3: Calculate the Difference in Interest
Difference
= ₹22,127.18 − ₹20,250
= ₹1,877.18 (Approx.)
Step 4: Calculate the Difference in Maturity Amounts
Difference
= ₹97,127.18 − ₹95,250
= ₹1,877.18 (Approx.)
Step 5: Calculate the Percentage by which Compound Interest Exceeds Simple Interest
Percentage Difference
= (Difference ÷ Simple Interest) × 100
= (1,877.18 ÷ 20,250) × 100
≈ 9.27%
Answer
- Simple Interest earned: ₹20,250
- Compound Interest earned: ₹22,127.18 (Approx.)
- Difference in interest earned: ₹1,877.18 (Approx.)
- Difference in maturity amounts: ₹1,877.18 (Approx.)
- Compound Interest exceeds Simple Interest by: 9.27% (Approx.)
So,
| Particulars | Pharmacist (Simple Interest) | Station Master (Compound Interest) |
| Principal | ₹75,000 | ₹75,000 |
| Rate | 9% p.a. | 9% p.a. |
| Time | 3 years | 3 years |
| Interest Earned | ₹20,250 | ₹22,127.18 |
| Maturity Amount | ₹95,250 | ₹97,127.18 |
| Extra Interest Earned | — | ₹1,877.18 More |
| Percentage More Interest | — | 9.27% |
Exam Tip (SSC, RRB, Banking, Defence & Police Exams)
When the principal is the same, remember these facts:
- Difference in Interest = Difference in Maturity Amount
- This is because both investments start with the same principal.
- If asked for the percentage by which Compound Interest exceeds Simple Interest, use:
Percentage Difference = (Difference ÷ Simple Interest) × 100
What We Learned in This Section
In this section, we learned how to calculate Simple Interest, Compound Interest, Maturity Amount, and the difference between SI and CI. We also practiced shortcut methods, reverse questions, percentage comparisons, and exam-oriented word problems involving investments and loans.
Related Topics
To strengthen your understanding, you should also learn:
- Percentage – The foundation of interest calculations.
- Ratio and Proportion – Useful for solving investment and finance problems.
- Profit, Loss and Discount – Frequently combined with Simple Interest and Compound Interest in competitive exams.
FAQ
1. Why is Compound Interest always greater than Simple Interest?
Compound Interest is usually greater than Simple Interest for periods longer than one year because interest is earned on both the principal and the accumulated interest, whereas Simple Interest is calculated only on the principal.
2. What is the shortcut formula for the difference between SI and CI?
- For 2 years: Difference = (P × R²) ÷ 100²
- For 3 years: Difference = P × R² × (300 + R) ÷ 100³
3. Can we use the 2-year shortcut for 3-year questions?
No. The 2-year shortcut is valid only for 2-year questions. For 3-year questions, use the dedicated 3-year shortcut formula or calculate SI and CI separately.
4. Which exams ask Difference Between SI and CI questions?
These questions are commonly asked in SSC, RRB, Banking, Defence, Police, State PSC, and other competitive examinations.
5. Is the difference between maturity amounts equal to the difference between interest amounts?
Yes. When the principal amount is the same, the difference between the maturity amounts is equal to the difference between the interest amounts
Important Resources Related to Difference Between Simple Interest and Compound Interest Questions with Answers and Solutions
- Simple Interest & Compound Interest
- Simple Interest Questions with Answers and Solutions
- Simple Interest & Compound Interest Formula with Examples and Explanations
- Compound Interest Questions with Answers and Solutions (15 Solved)
- Compound Growth Questions with Answers and Solutions
- Depreciation Questions with Answers and Solutions
- Simple Interest & Compound Interest Practice Questions
- Simple Interest & Compound Interest PYQs SSC, RRB, Banking & Defence Exams With Solution.